LeetCode 58: Length of Last Word

LeetCode String

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

代码

C语言版本：

int isChar(char p) {  
    return ('a'<=p && p<='z')||('A'<=p && p<='Z');  
}  
int lengthOfLastWord(char* s) {
    int size = strlen(s);
    int begin;
    int end = size - 1;
    if (size < 1) {
        return 0;
    }
    while(end >= 0 && s[end] == ' ') {
        end--;
    }
    begin = end;
    while ( begin >= 0 && isChar(s[begin])) {
            begin--;
    }
    return end - begin;
}